2. Lissajous Bridge 6 pts

Electricity · AC circuits, Phasors, AC bridge, Lissajous figures

Find the on-screen amplitude of the xx-channel signal at the slider position that collapses the oscilloscope Lissajous trace into a line segment.

High-level summary by Claude.

Ingredients phasor algebracomplex impedancevoltage dividerLissajous-line conditionAC bridge balance
Tags ac-circuitsphasor-analysiscomplex-impedanceac-bridgelissajous-figureoscilloscoperc-filterrl-filter

Difficulty medium

Prerequisites

  • Phasor representation of sinusoidal signals at one frequency
  • Complex impedance: ZC=1/(jωC)Z_C = 1/(j\omega C), ZL=jωLZ_L = j\omega L
  • Voltage-divider formula for two impedances in series
  • Lissajous figure \to line segment iff VxV_x and VyV_y are in phase (or anti-phase)
  • Potentiometer modelled as a uniform resistor with a tap at fractional length

Learning objectives

  • Translate an RCRC/RLRL filter network into phasors with the source as real reference
  • Recognise the Lissajous-line condition as Vy/VxRV_y/V_x \in \mathbb{R} and turn it into one real equation
  • Identify a real, in-phase tap (the slider VPV_P) as the analogue of the variable arm in a Wheatstone bridge
  • Show that a balanced AC bridge gives a frequency-independent relation between RR, LL, CC — and that the residual slope of the line encodes the frequency
  • Read amplitude information off a Lissajous trace by projecting onto the screen axes

Watch out for

  • VPV_P is real (in phase with the source); VBV_B and VDV_D are not. The whole bridge trick relies on this asymmetry.
  • Slider geometry: with AA on the left and EE on the right, the ratio 1:21{:}2 from left to right means AP=13AEAP = \tfrac{1}{3}AE, so VP=23VV_P = \tfrac{2}{3}V — not 13V\tfrac{1}{3}V.
  • The slope tanα\tan\alpha is necessarily negative in this circuit; always 2<tanα<12-2 < \tan\alpha < -\tfrac{1}{2}. A positive answer for tanα\tan\alpha signals a sign error somewhere in the phasor algebra.
  • Don't confuse the balance condition L=2R1R2CL = 2R_1R_2C (a property of the components, frequency-independent) with the slope (which does depend on ω\omega).
  • VBP|V_{BP}| is the half-extent of the line segment along the xx-axis, not the full length of the line — the latter would also include the yy-projection.