2. Evaporation Jaan Kalda 7 pts

Thermodynamics · Phase transitions, Diffusion, Heat transfer

Piston–cylinder equilibrium with saturated vapour, and derivation of the wet-bulb temperature of sweating skin in a sauna.

Problem by Jaan Kalda.

For the subsequent tasks, the graph shows how the density of saturated water vapour in gm3\text{g\,m}^{-3} depends on the temperature in °C.

Graph: water vapour density ρ (g/m³) vs temperature T (°C), ranging from 40 °C to 105 °C, values from roughly 50 to 800 g/m³

You may also use the following characteristics of water. Specific heat capacity c=4200 Jkg1K1c = 4200\ \text{J\,kg}^{-1}\text{K}^{-1}; latent heat of vaporization L=2260 kJkg1L = 2260\ \text{kJ\,kg}^{-1}; density ρ=1000 kgm3\rho = 1000\ \text{kg\,m}^{-3}; molar mass of water μ=18 gmol1\mu = 18\ \text{g\,mol}^{-1}. You may also assume water vapour to behave as an ideal gas. The universal gas constant is R=8.31 Jmol1K1R = 8.31\ \text{J\,mol}^{-1}\text{K}^{-1}.

i) (2 points) A cylinder contains a certain amount of water at temperature T0=90 °CT_0 = 90\ °\text{C}. The cross-sectional area of the piston is S=1 dm2S = 1\ \text{dm}^2. What is the minimum pulling force required to move the piston? The pressure of the surrounding air is p0=100 kPap_0 = 100\ \text{kPa}.

Diagram of a piston-cylinder: water (H₂O) on the left, air at 1 atm on the right

ii) (2 points) If the piston is pulled so that it shifts by a=3 dma = 3\ \text{dm}, the water cools to a temperature of T1=89 °CT_1 = 89\ °\text{C}; what is the mass of the water under the piston?

Water evaporation has a cooling effect the intensity of which depends on the relative humidity and air convection intensity. It appears, however, that once a dynamical thermal equilibrium is reached, the equilibrium temperature of a wet surface depends only on the relative humidity and the temperature of air and does not depend on the convection speed (as long as the convection is not too weak). This is so because the two competing processes determining the equilibrium state both depend on the thickness of the laminar (non-turbulent) surface layer exactly in the same way. In what follows we shall use the following assumptions:

  • (a) Atop a wet surface (such as a sweating bare skin), there is a layer with a laminar flow of a certain thickness dd.
  • (b) Atop the laminar layer, the surrounding turbulent flow keeps a constant temperature TT and relative humidity rr, both equal to the respective values in the bulk of the surrounding air.
  • (c) Heat flux from beneath the wet surface (e.g. through the skin) can be neglected.
  • (d) The heat conductivity of air κ=30 mWm1K1\kappa = 30\ \text{mW\,m}^{-1}\text{K}^{-1} at T=70 °CT = 70\ °\text{C} (neglect the temperature dependence), and the diffusivity of water molecules in air D=26 mm2s1D = 26\ \text{mm}^2\text{s}^{-1}. Neglect the dependence of DD on the temperature. Note that the particle flux (net number of molecules passing a cross-section in the yyzz-plane per second and per cross-sectional area) can be found as J=DdndxJ = D\,\dfrac{dn}{dx}, where nn denotes the number density (number of molecules per volume).

iii) (3 points) Determine the temperature of sweating human skin in a sauna if the air temperature T=110 °CT = 110\ °\text{C} and r=3%r = 3\%.