10. Ball Magnet Exp Jaan Kalda 10 pts

Electromagnetism · Magnetostatics, Magnetic dipole, Geomagnetism, Paramagnetism

Using a ball-shaped neodymium magnet as a calibrated point dipole, locate its magnetisation axis, measure the strength of the Earth's magnetic field, and extract the magnetic susceptibility of a small titanium wire piece from the force on it in the magnet's inhomogeneous field.

Problem by Jaan Kalda.

Tools: ball-shaped neodymium magnet of diameter d=10mmd = 10\,\text{mm} with remanence Br=1.2TB_r = 1.2\,\text{T}, density ρM7500kgm3\rho_M \approx 7500\,\text{kg}\cdot\text{m}^{-3}; stand; permanent marker; ruler; measuring tape; flat iron disk; square wooden plate with an iron pin inserted at one side; flat wooden plate with guiding rails and non-slipping surface between them; piece of titanium of diameter 2.4mm2.4\,\text{mm} and length 3.4mm3.4\,\text{mm} fixed to a string. Density of titanium ρTi4500kgm3\rho_\text{Ti} \approx 4500\,\text{kg}\cdot\text{m}^{-3}.

A uniformly magnetised sphere produces an external field identical to that of a point magnetic dipole with a moment μ=43πR3Br/μ0\mu = \frac{4}{3}\pi R^3 B_r/\mu_0, where RR is the sphere’s radius. Along the axis of a dipole, B=μ0μ/(2πr3)\vec{B} = \mu_0 \vec{\mu}/(2\pi r^3), where rr is the distance from the dipole. The dipole moment of the Earth is pointing southwards.

Warning: measure as far as possible from iron objects (table frames, chairs), which strongly perturb the geomagnetic field.

i) (2 points) Find the direction of the magnetisation of the magnet: mark on its surface a dot at the point where the straight magnetic field line exits, and a cross where it enters.

Before leaving the room, give the magnet with the markings to the invigilator.

ii) (4 points) Find the magnitude of the Earth’s magnetic field BE|\vec{B}_E| at the laboratory location.

iii) (4 points) Titanium is a paramagnetic material with magnetic susceptibility χ1\chi \ll 1. A small sample of volume VV in an inhomogeneous field B(r)\vec{B}(\vec{r}) experiences a force F=12(χV/μ0)gradB2\vec{F} = \frac{1}{2}(\chi V/\mu_0)\,\text{grad}\,B^2 (‘grad’ denotes derivative in the direction of greatest change). Find χ\chi for the supplied titanium wire piece.