2. Evaporation 7 pts

Thermodynamics · Phase transitions, Diffusion, Heat transfer

Piston–cylinder equilibrium with saturated vapour, and derivation of the wet-bulb temperature of sweating skin in a sauna.

High-level summary by Claude.

Ingredients saturated vapour pressurelatent heat of vaporisationFick's law of diffusionsteady-state flux balancewet-bulb temperature
Tags thermodynamicsphase-transitionssaturated-vaporlatent-heatideal-gasfick-lawfourier-lawwet-bulbevaporative-coolinggraphical-solution

Difficulty medium

Prerequisites

  • Ideal gas law pV=nRTpV = nRT and p=ρRT/μp = \rho RT/\mu
  • Concept of saturated vapour pressure and phase equilibrium
  • Fourier's law of heat conduction, q=κTq = -\kappa\,\nabla T
  • Fick's law of diffusion, J=DnJ = -D\,\nabla n
  • Latent heat LL as an enthalpy (already includes pΔVp\,\Delta V work)
  • Steady-state 1D transport → linear profiles

Learning objectives

  • Identify when a saturated-vapour pressure (not atmospheric) sets the mechanical equilibrium of a liquid–gas interface
  • Write a latent-heat balance for evaporative cooling and justify dropping the vapour mass on the liquid side
  • Recognise that, in steady state, conduction and diffusion fluxes in a laminar layer share the same 1/d1/d scaling so the layer thickness cancels
  • Reduce coupled heat-and-mass transport to a single implicit equation for the wet-bulb temperature
  • Solve a transcendental equation graphically by overlaying a straight line on the saturation curve
  • Explain why a dry sauna at 110 °C110\ °\text{C} is tolerable but the same temperature at 100% humidity is not

Watch out for

  • Treating LL as an internal-energy change. LL is the enthalpy of vaporisation and already bakes in the pΔVp\,\Delta V work the vapour does on the piston — adding a separate pΔVp\,\Delta V term double-counts.
  • Setting the vapour pressure equal to atmospheric. Saturated vapour pressure at 90 °C90\ °\text{C} is only ~70 kPa70\ \text{kPa}, well below atmospheric; water is liquid in the initial state, and the force calculation is driven by the 30 kPa30\ \text{kPa} deficit.
  • Forgetting that at the wet skin surface the relative humidity is 1 (rs=1r_s = 1), regardless of the bulk rr. The density at x=0x = 0 is ρsat(Ts)\rho_{\text{sat}}(T_s), not rρsat(Ts)r \cdot \rho_{\text{sat}}(T_s).
  • Keeping dd in the final balance. Both fluxes scale as 1/d1/d in steady state, so dd cancels — this is the whole reason the wet-bulb temperature is a well-defined material property of the air state.
  • Mixing up flux signs. Heat flows from hot air down to cool skin; water vapour flows up from the wet skin to drier air. The two fluxes are anti-parallel and the energy balance uses their magnitudes.