3. Nuclear Reactors 6 pts

Modern Physics · Nuclear physics, Elastic collisions, Ideal gas

Neutron moderation in a thermal reactor — speeds, temperatures, number of collisions to thermalise, and gas buildup in spent fuel rods.

High-level summary by Claude.

Ingredients non-relativistic kinetic energyelastic central collisionsequipartition theoremBoyle's lawDalton's law of partial pressures
Tags nuclearfissionmoderatorelastic-collisionsequipartitionideal-gasboyle-lawdalton-lawpartial-pressurenon-relativistic-limit

Difficulty medium

Prerequisites

  • 1D elastic collisions (energy + momentum conservation)
  • Non-relativistic kinematics, Ek=12mv2E_k = \tfrac{1}{2} m v^2
  • Ideal gas law, pV=nRTpV = nRT
  • Equipartition theorem / Maxwell–Boltzmann distribution
  • Boyle's law and Dalton's law

Learning objectives

  • Justify the non-relativistic limit via the small parameter Ek/mc2E_k / m c^2
  • Apply energy + momentum conservation to derive the 1D elastic-collision identity v1+v1=v2+v2v_1 + v_1' = v_2 + v_2'
  • Identify the moderator mass that maximises neutron energy transfer (M=mnM = m_n) and explain why hydrogen is the gold-standard moderator
  • Model repeated head-on elastic collisions as geometric decay of speed, vN=v0αNv_N = v_0\,\alpha^N
  • Distinguish the mode (E=kBTE = k_B T) and mean (E=32kBTE = \tfrac{3}{2} k_B T) of a Maxwell–Boltzmann distribution
  • Combine Boyle's law and Dalton's law to analyse a gas mixture at constant temperature

Watch out for

  • Mode-vs-mean confusion in Maxwell–Boltzmann. The oft-quoted 0.025 eV0.025\ \text{eV} is kBTk_B T at room temperature (the most-probable energy), not 32kBT\tfrac{3}{2} k_B T (the average). Reading the problem literally requires 32kBT\tfrac{3}{2} k_B T and gives Tf193 KT_f \approx 193\ \text{K}, not 290 K290\ \text{K}.
  • Forgetting the volume change in part (iv). The rod's free volume drops from V0V_0 to VV due to pellet swelling; the helium partial pressure in the final state must be computed with the new volume via Boyle's law before applying Dalton's law.
  • Treating all elastic collisions as head-on. The problem explicitly asks for head-on collisions, but the realistic "logarithmic energy decrement" formula gives roughly twice as many collisions to thermalise, which is often quoted in reactor physics literature.
  • Dropping the sign in α=(mnM)/(mn+M)\alpha = (m_n - M)/(m_n + M). For M>mnM > m_n, α\alpha is negative; solving vN=v0αNv_N = v_0\,\alpha^N for NN requires taking α|\alpha| so that the logarithm is real.